Find the answer to the question please 16t^4/8t

STEP

1

:

Equation at the end of step 1

 ((16 • (t4)) -  23t2) +  1

STEP

2

:

Equation at the end of step

2

:

 (24t4 -  23t2) +  1

STEP

3

:

Trying to factor by splitting the middle term

3.1     Factoring  16t4-8t2+1

The first term is,  16t4  its coefficient is  16 .

The middle term is,  -8t2  its coefficient is  -8 .

The last term, "the constant", is  +1

Step-1 : Multiply the coefficient of the first term by the constant   16 • 1 = 16

Step-2 : Find two factors of  16  whose sum equals the coefficient of the middle term, which is   -8 .

     -16    +    -1    =    -17

     -8    +    -2    =    -10

     -4    +    -4    =    -8    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -4  and  -4

                    16t4 - 4t2 - 4t2 - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

                   4t2 • (4t2-1)

             Add up the last 2 terms, pulling out common factors :

                    1 • (4t2-1)

Step-5 : Add up the four terms of step 4 :

                   (4t2-1)  •  (4t2-1)

            Which is the desired factorization

Trying to factor as a Difference of Squares:

3.2      Factoring:  4t2-1

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  4  is the square of  2

Check : 1 is the square of 1

Check :  t2  is the square of  t1

Factorization is :       (2t + 1)  •  (2t - 1)

Trying to factor as a Difference of Squares:

3.3      Factoring:  4t2 - 1

Check :  4  is the square of  2

Check : 1 is the square of 1

Check :  t2  is the square of  t1

Factorization is :       (2t + 1)  •  (2t - 1)

Multiplying Exponential Expressions:

3.4    Multiply  (2t + 1)  by  (2t + 1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (2t+1)  and the exponents are :

         1 , as  (2t+1)  is the same number as  (2t+1)1

and   1 , as  (2t+1)  is the same number as  (2t+1)1

The product is therefore,  (2t+1)(1+1) = (2t+1)2

Multiplying Exponential Expressions:

3.5    Multiply  (2t-1)  by  (2t-1)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (2t-1)  and the exponents are :

         1 , as  (2t-1)  is the same number as  (2t-1)1

and   1 , as  (2t-1)  is the same number as  (2t-1)1

The product is therefore,  (2t-1)(1+1) = (2t-1)2

Final result :

 (2t + 1)2 • (2t - 1)2

Step-by-step explanation:

in mathematics, a function is a relationship between two variables such that the value of one of the variables, called the dependent variable, is determined by the value of the other variable, called the independent variable. there is a specific term we use to describe the set of independent variables of a function.

{3 + i, 3 - i, 3, -1}

step-by-step explanation: