The body of a 154-pound person contains approximately milligrams of gold and milligrams of aluminum. based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?

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Complete Question

The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.

Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?

300 times

Step-by-step explanation:

From the above question, we are told:

The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.

We create a proportion

2 × 10^-1 mg of gold : 6 × 10^1 mg of aluminum

= 0.2 mg of gold : 60 mg of aluminum

Therefore, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body is calculated as:

60mg ÷ 0.2 mg

= 300

Therefore, the number of milligrams of aluminum in the body is 300 times the number of milligrams of gold in the body

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.

17 1/3

step-by-step explanation: