Evaluate 8p + 3q - 18 when p=1/2 and q=7

7

Step-by-step explanation:

Step 1: Define

Equation: 8p + 3q - 18

p = 1/2

q = 7

Step 2: Substitute

8(1/2) + 3(7) - 18

Step 3: Evaluate

4 + 21 - 18

25 - 18

7

the forst and 3rd

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.