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The Asymptote would be at -3

Step-by-step explanation:

Just remember, when the number at the bottom (not the x) is positive, the graph would shift left by that number. And if it is negative, the graph would translate right by that number.

Since the function has positive 3, the asymptote is at -3

If the function was -3, the asymptote is at 3

EXTRA STUFF: If there is a number next to the fraction, that is not part of the denominator, then that is where the horizontal asymptote would be.

true? is that what you're asking or do you mean something else?

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

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m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0