Choose a postmenopausal woman at random. The probability is 0.46 that the woman chosen has osteopenia (low but not pathologically low bone density ) and 0.09 that she has osteoporosis (pathologically low bone mineral density. Assume that a woman can't have both diseases simultaneously. (a) What is the probability that a randomly chosen postmenopausal woman has a healthy bone density

The probability that a randomly chosen postmenopausal woman has a healthy bone density is 0.45.

Step-by-step explanation:

Probability of the postmenopausal woman having osteopenia = 0.46

Probability of the postmenopausal woman having osteoporosis = 0.09

Probability of having either osteopenia or osteoporosis = 0.55 (0.46 + 0.09).

Therefore, the probability that the postmenopausal woman does not have either osteopenia or osteoporosis, which is the same as having a healthy bone density = 0.45 (1 - 0.55).  

8/k

step-by-step explanation:

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )