The probability for event A is 0.4, the probability for event B is 0.2, and the probability of events A and B is 0.1. Why are the events are not independent?
The sum of P(A) and P(B) is greater than P(A and B).
The product of P(A) and P(B) is greater than P(A and B).
The product of P(A) and P(B) is not equal to P(A and B).
The sum of P(A) and P(B) is not equal to P(A and B).

the answer is -product of P(A) and P(B) is not equal to P(A and B)

C. The product of P(A) and P(B) is not equal to P(A and B).

Step-by-step explanation:

right on edge

none cuz there are no "following statements" regarding the question

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560