question 3 the three straight paths, AB, BC, and AC, meet each other at three points. A, B, and C. How do these points of intersection differ from each other? explain the differences in terms of the angles that you see. Also look at the length of the side opposite each angle. What pattern do you see regaurding the measurments? in what situation would all the points of intersection resemble one another? Modify the triangle in geogebra to help you with your answers.

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: