If a standard 6 sided dice is rolled. (Write your answers as a decimal, rounded to the nearest hundredth.) Find: a. Probability of rolling one die and it landing on both a prime number and a multiple of two. b. Probability of rolling one die and it landing on a 3 or a prime number. c. P(3 U Multiple of 2) = d. P(2 U Even number) =

see below

Step-by-step explanation:

The possible outcomes are 1,2,3,4,5,6

P( a prime number and a multiple of two)

The only prime number that is a multiple of 2 is 2

P( a prime number and a multiple of two) = number of outcomes / total outcomes

P( a prime number and a multiple of two) = 1/6 = .17

P(3 or a prime number)

The prime numbers are 2,3,5  and 3 is included in this list so we have 3 outcomes

P( 3 or a prime number) = number of outcomes / total outcomes

P( 3 or a prime number) =3/6 =1/2= .5

P(3 U Multiple of 2)

Multiples of 2 are 2,4,6 and add 3 to the list  so there are 4 outcomes

P( 3 U Multiple of 2) = number of outcomes / total outcomes

P( 3 or a prime number) =4/6 =2/3= .67

P(2 U Even number)

even numbers are 2,4,6 and 2 is on the list  so there are 3 outcomes

P( 2 U Even number) = number of outcomes / total outcomes

P( 3 or a prime number) =3/6 =1/2= .5

18.36. give me brainliest!

step-by-step explanation:

you have to multiply 1.53 by 12 so the equation is 12x1.53 and then that is your answer.