Each week, Mrs. Stafford picks a runner from her homeroom to run errands. In order to remain unbiased in her selection, she flips a coin to determine if
the runner will be a boy or a girl. She assigns heads to girls and tails to boys.
1. Based on this procedure, what is the probability of
selecting a boy?
2. Suppose after 20 weeks, Mrs. Stafford has tossed tails
16 times. Based on this observed frequency, what is the probability that a
boy will be selected next week?

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

↓↓↓↓↓↓↓↓↓

step-by-step explanation:

this is a parabola.

there is only one way to arrange all the eight relative to each other because they are not distinct. we have

now there are nine places to place an (and not more than one in one place).   because we have four symbols, we need to choose four of these nine places to insert an . order does not matter because the are not distinct.

thus there are 1 · c(9,4) ways, or, if we calculate it,

thus there are 126 ways to form such "words."

i have no idea

step-by-step explanation:

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