Annika was having fun playing poker. She needed the next two cards dealt to be diamonds so she could make a flush (five cards of the same suit). There are 15 cards left in the deck, and five are diamonds. What is the probability that the two cards dealt to Annika (without replacement) will both be diamonds

10%

Step-by-step explanation:

given data:

no of cards left = 15.

no of diamonds left = 5.

probability of drawing a diamond = 5/15.

probability that the next two cards drawn to anika are diamonds without replacements.

= 5/15 * 4/14

= 2/21

= 0.0952 * 100

the probability that the two cards dealt to Anika would be diamond is 9.52% ~ 10%

step-by-step explanation:

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %