–6c = –7 − 5c Solve Please

c = 7

Step-by-step explanation:

Isolate the variable c. Note the equal sign, what you do to one side, you do to the other.

First, add 5c to both sides of the equation:

-6c (+5c) = -7 - 5c (+5c)

-6c + 5c = -7

-c = -7

Isolate the variable, c. Divide -1 from both sides of the equation:

(-c)/-1 = (-7)/-1

c = -7/-1

c = 7

c = 7 is your answer.

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∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

a

b

d

step-by-step explanation: