Write the equation of a line that is parallel to y=6x+1 and that passes through (-7,1)

y = 6x + 43

Step-by-step explanation:

Our unknown line is of the form

y = kx + m

Where k is the slope of the line.

Since our line is parallel to 6x+1, the slope of the two lines must be equal. In other words, the two must have the same value of k.

In our line 6x+1, the k value is 6.

Thus, our unknown line must look like this:

y = 6x + m

Now, we need to find out what m is. Our line passes through (-7, 1).

Thus, we know that when x is equal to -7, y is equal to 1,

We can put these two values:

x = -7

y = 1

...into our line to find m.

y = 6x + m

1 = 6 * (-7) + m

Since 6 * (-7) = -42

1 = - 42 + m

1 = m - 42

Now, we can add 42 to both sides:

1 + 42 = m - 42 + 42

43 = m

m = 43

Our line has the k-value of 6, and m-value of 43. As such, the equation will be the following:

y = kx + m

y = 6x + 43

y = 6x + 43

answer: 2530

hope this

answer: 193

explanation:

200-7 = 193