You are given the equation (2x^ny^2)^m = 4x^6y^4. Find two positive integers, m and n, that make the equation true.

Step-by-step explanation:

Given

Required

Solve for m and n

Start by opening the bracket using laws of indices

Express 4 as 2²

Compare both sides of the equation, we have:

--- (1)

--- (1)

 ---- (2)

In (1)

2 cancels out on both sides; so, we have

In (2)

x cancels out on both sides; so, we have

Substitute 2 for m

Divide through 2

In (3)

y cancels out on both sides; so, we have

Divide through 2

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

angle addition postulate

2x=56

step-by-step explanation: