square root of x plus 6 β 4 = x
Mathematics, 01.12.2019 00:31, 719563mercy
Israel started to solve a radical equation in this way:
square root of x plus 6 β 4 = x
square root of x plus 6 β 4 + 4 = x + 4
square root of x plus 6 = x + 4
(square root of x plus 6)2 = (x + 4)2
x + 6 = x2 + 8x + 16
x + 6 β 6 = x2 + 8x + 16 β 6
x = x2 + 8x + 10
x β x = x2 + 8x + 10 β x
0 = x2 + 7x + 10
0 = (x + 2)(x + 5)
x + 2 = 0 x + 5 = 0
x + 2 β 2 = 0 β 2 x + 5 β 5 = 0 β 5
x = β2 x = β5
solutions = β2, -5
what mistake did isreal make?
a) he subtracted 6 before subtracting x. b) he added 4 before squaring both sides. c) he factored x2 + 7x + 10 incorrectly. d) he did not check for extraneous solutions.
Answers: 1
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Israel started to solve a radical equation in this way:
square root of x plus 6 β 4 = x
square root of x plus 6 β 4 = x
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