The velocity of a ball is thrown up is 20 meters/second. it attains zero velocity after 3.5 seconds. what is the average acceleration of the ball during its upward flight?

Acceleration = 5.714 meter per second²

Step-by-step explanation:

A ball has been thrown up with a speed of 20 meters per second.

After 3.5 seconds speed of the ball become zero that means ball attains it's maximum height after 3.5 seconds.

Now we have to calculate the average acceleration during the upward motion.

Since,

Acceleration =

                     = 5.714 meter per second²

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

b

step-by-step explanation:

it have 5 sides and 5 identicle angle.the rest does not have the same property as b.

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