in the backwaters of Kerala a boatman was throwing a Boat using a long pole of length 4.80 when he put the pole vertically into the water so that the pole touch the ground under the water 0.25 part of the pole was above the water level what is the depth of the water at that point

3.60m

Step-by-step explanation:

In backwaters of Kerala, a boatman was throwing a boat with a long pole which has a length of 4.80m

The boatman put the pole into the water vertically, the part of the pole that was seen above the water level is 0.25m

The first step is to calculate the length of the pole that is seen above the water level

= 4.80 × 0.25

= 1.20m

Therefore the depth of the water at that point can be calculated as follows

=4.80m - 1.20m

= 3.60m

Hence the depth of the water at that point is 3.60m

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.