Suppose a charity event serves a prix fixe dinner that consists of one from each category: (1) soup or salad (not both), (2) appetizer, (3) entree, (4) dessert, and (5) beverage. The restaurant is offering five kinds of soup, three kinds of salad, four kinds of appetizers, six entrees, five desserts, and four beverages. How many different prix fixe dinners are possible

3840

Step-by-step explanation:

Using the fundamental counting principle

The restaurant is offering five kinds of soup, three kinds of salad, four kinds of appetizers, six entrees, five desserts, and four beverages.

There are 5 independent events happening (5 prixe dinners)

(1) soup or salad (not both)

We have five kinds of soup, three kinds of salad

soup or salad (not both), = 5 + 3

= 8

(2) appetizer = 4

(3) entrees = 6

(4) dessert = 5

(5) Beverage = 4

Hence,

8 × 4 × 6 × 5 × 4

= 3840

The number of different prix fixe dinners are possible is 3840

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

this answer is !