A basketball player makes 80% of his free throws. We set him on the free throw line and told him to shoot free throws until he misses. Let the random variable X be the number of free throws taken by the player until he misses. Assuming that his shots are independent, what is the probability of this player missing a free throw for the first time on the fifth attempt

0.08192

Step-by-step explanation:

Given: Probability of free throws = 0.80

Then, probability of missing the free throw = 1-0.80=0.20

Now, According to the negative binomial probability distribution, the probability that the rth success is achieved in xth trial is given by ;-

Put p = 0.20 , x=5 and r =1, we get

The probability of this player missing a free throw for the first time on the fifth attempt as

hence the required probability =0.08192

step-by-step explanation:

the first 5 right here the next 5 i will upload as separate question

d

step-by-step explanation:

hello and welcome!

so, when we see the words "proportional" along with a table, we need to know that we're looking numbers that divide by the same thing.

looking at this table, we simply have to do a trial and error, and divide to see which numbers have the same quotient. if you look at choice a & c, they both have equal quotients for three of the numbers, with one exception, so those can't be the answer. looking at b, there is no similarity, so that can't be it. then, we see d; if you divide all the numbers in the table, you'll see that they all divide by two, which is a proportional relationship, and our answer!

also, always remember that the x will always be the number that goes into y, and somewhere behind this table, is a formula. for this specific table, the formula would be:

since our x-value is being divided by two to get the y-value. and if they were to ask for more numbers in the series, this is the formula you would use to find them.