A class of 128 students from civil, mechanical and electrical engineering backgrounds is divided into 2 sections (sections A and B). Section A contains of 18 civil engineers and a total of 50 students. Section B contains 44 mechanical engineers. There are a total 40 civil engineers and 60 mechanical engineers in the class. What is the probability that a random electrical engineering student is from section A

The probability is 0.5714

Step-by-step explanation:

This is a probability question. We are interested in calculating the probability that a random electrical engineering student is from section A.

Mathematically the probability will be;

Number of electrical engineering students in section A/ Total number of electrical engineering students in both sections

Total number of electrical engineering students = 128 - 60 -40 = 28

Now let’s calculate the number of electrical students from section A

Number of mechanical and electrical = 50-18 = 32

Now, there are a total of 60 mechanical engineers and 44 in B; So the number of mechanical engineers in A = 60-44 = 16

So the number of electrical engineers in A = 32-16 = 16

So the probability will be;

16/28 = 4/7 = 0.5714

i think it is c, not positive though

step-by-step explanation: