Moses and leillah are still playing the game "guess my numbers". it is leillah's turn.
leillah: i am thinking of two numbers their greatest common factor is 3 and their least common multiple is 90.
moses: there are exactly three possible pairs of numbers that you could be thinking of.
is moses right? if you agree with moses, explain how you know that there are exactly three possible pairs of numbers.
if you disagree, find all possible pairs of numbers that leillah might be thinking of.

answer: sorry

step-by-step explanation: can you tell me pls how to find the rational of two integers

you have to wait a while to reward brainliest if only one person answers. if 2 people answer there should be a "mark brainliest" on their question.

i cant fully remember all of the ranks, here are the ones i remember.

hand, ambitous, ace, genius.

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.