A certain field is a rectangle with a perimeter of 846
feet. The length is
159
feet more than the width. Find the width and length of the rectangular field.

Width = 132 feet, Length = 291 feet

Step-by-step explanation:

perimeter (P) = 846

let width(W) = x

length(L) = 159 feet more than width = 159 + W= 159 + x

P of a rectangle = 2*(L + W)

846 = 2*((159 + x) + x)

divide both side by 2

423 = (159 + x) + x

423 = 159 + 2x

rearranging

2x + 159 = 423

2x = 423 -159

2x = 264

divide both sides by 2

x = 132 feet

recall W = x and L = 159 + x

W = 132 feet

L = 159 + 132 = 291 feet

i pretty sure it is

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.