A local zoo has two large snakes. The anaconda is currently 5.23 meters long and grows 1.27 meters every month. The python is 4.76 meters long and grows 2.04 meters per month. How many months ( ) m does the zookeeper need to wait for the two snakes to be the same length? a. Write the question or problem statement for the situation. b. Write the general form of the equation. c. Write the verbal and variable expression for the left side of the equation. d. Write the verbal and variable expression for the right side of the equation. e. Write the final algebraic equation with variables on both sides. Include what the variable represents in the problem. Include appropriate units.

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Step-by-step explanation:

a.  We want to see when the two snakes will be the same length.

b.   b1 + r1m= b2 + r2m  where b is the initial length and m is the number of months and r is the  growth rate

c.   for the anaconda  5.23 + 1.27 m  where m is the number of months,  and the total length is in meters

The anaconda starts at 5.23 meters and grows 1.27 meters each month for m months

d.  for the python 4.76 + 2.04m   where m is the number of months, l is the length of the python in meters

The python starts at 4.76 meters and grows 2.04 meters each month for m months

e.  5.23 + 1.27 m  = 4.76 + 2.04m   m is the number of months  Each side is the number of meters

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

step-by-step explanation: