The perimeter of a rectangular playing field is 280 feet. The length of the field is 20 feet more than the width. What are the dimensions of the playing field? (You need to find the length and the width.)

L =80

w=60

Step-by-step explanation:

P =280

L =w +20

=>L +w=280 :2 =140

w+20+w=140

2w=140 - 20

2w =120

w=120 :2 =60

L=60 +20 =80

P =2L +2w

P =2 ×80 +2 ×60

P=160 +120

P=280

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

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im not sure