At a movie theater, tickets for children cost $6.05 each and adult tickets cost $8.75 each. If ticket sales for a group of 35 people total $259. How many children were in this group?

More unknown than equations, the answer cannot be determined

Step-by-step explanation:

We can solve by means of a 2x2 system of equations, we have to:

"x" is the number of children's tickets

"y" is the number of adult tickets

Thus:

blank * x + 8.75 * y = 259

x + y = 35

which means that the number of children in the group cannot be calculated with the supplied data, this is because we have 3 unknowns and there are 2 equations, which means that the system has no solution.

If we assume a value, for example, $ 5

We can solve:

5 * x + 8.75 * y = 259

x + y = 35 => x = 35 - y

replacing we have:

5 * (35 - y) + 8.75 * y = 259

175 - 5 * y + 8.75 * y = 259

- 5 * y + 8.75 * y = 259 - 175

3.75 * y = 84

y = -84 / 3.75

y = 22.4

Thus:

x = 35 - (22.4) = 12.6

there being then 22 adults and 13 children.

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

u bout ugly as   a mf

step-by-step explanation: lol