Joes mother gave him 1/3 of the money in her purse. His father gave him 5.00. If they gave joe a total of 12.00, How much money did his mother have in her purse. Joes mother had $ money in her purse (Enter a number only and make sure to include the decimal and 2 numerical decimal places.)

Step-by-step explanation:

let the money in her purse be $x

1/3 of the money is 1/3x

Since his father gave him $5 and the total amount became $12

the expression for the total amount would be

12= 1/3x+5

We can now solve for x

12-5= 1/3x

1/3x= 7

cross multiply we have

x= 7*3

x= $21

Therefore the money in joes mother's purse is $21

answer. d.289 hope that

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)