ASAP Water flowed out of a tank at steady rate. A total of 18 1/2 gallons flowed out of a tank in 4 1/4 hours. Which expression determines the the quality of water leaving the tank per hour?
O 17/4 divide 36/2
O 36/2 divide 17/4
O 17/4 divide 37/2
O 37/2 divide 17/4

In 1 hour water flowed out = 74/17  gallons

Step-by-step explanation:

Given as ,

The quantity of water flowed out of tank =  18 1/2 gallons

                                                                  =   37/2   gallons

The time spend in flowing water out of tank = 4  1/4 hours

                                                                         =   17/4   hours

∵ In   17/4 hours , water flowed out = 37/2

∴ In    1    hours                           ,  water flowed out =

So, in 1 hour water flowed out =  37*4/17*2 gallons Answer

none cuz there are no "following statements" regarding the question

step-by-step explanation: