For which values of a the system has at least one solution: x≤7 x≥a urgent pls help now

We have the system:

x ≤ 7

x ≥ a

Now we want to find the possible values of a such that the system has, at least, one solution.

First, we should look at the value of a where the system has only one solution:

We can write the 2 sets as:

a ≤ x

x ≥ 7

So, writing both together:

a ≤ x ≤ 7

if a is larger than 7, we do not have solutions.

then a = 7 gives:

7 ≤ x ≤ 7

Here the only solution is 7.

Now, if a is smaller than 7, for example 5, we have:

5 ≤ x ≤ 7

Now x can take different values, so we have a lot of solutions.

Then the restrictions for a, such that the system has at least one solution, is:

a ≤ 7.

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

b. b < 1 might be the correct answer