Sun^4A+sin^2Acos^2A=sin^2A

Step-by-step explanation:

sin⁴A + sin²Acos²A = sin²A

Proving the left hand side ( LHS)

That's

sin⁴A can be written as ( sin²A)(sin ²A)

So we have

( sin²A)(sin ²A) + sin²Acos²A

Next factor sin²A out

That's

sin²A ( sin²A + cos²A)

Using trigonometric identities

That's

Simplify the expression

That's

sin²A × 1

We have the final answer as

As proven

Hope this helps you

need points to ask question

step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,