50 Points Please answer fast, you just gotta match them with whichever goes with which. Complete the proof below by matching the statement to the correct reason. *Note: There are two reasons that are the same. Use option 1 for the first time you use that reason and option 2 for the second time you use that reason. Definition of Right Angle Given (option 2 ) Definition of Complementary Angles Given (option 1) Angle Addition Postulate Substitution Property Congruent Complements Theorem 1. ∠PQR is a right angle 2. m∠PQR = 90° 3. m∠PQS + m∠SQR = ∠PQR 4. m∠PQS + m∠SQR = 90° 5. ∠PQS and ∠SQR are complementary angles. 6. ∠TQP and ∠SQR are complementary angles. 7. ∠PQS ≅ ∠TQP

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the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2