The equation of line ab is y = 5x + 1. write an equation of a line parallel to line ab in slope-intercept form that contains point (4, 5).

y = 5x − 15

y = 5x + 15

y = 1 over 5x + 21 over 5

y = 1 over 5x − 29 over 5

The equation of the line y = 5x + 1. Line that is parallel to the function given should have the same slope as the equation which is 5. We use the point-slope form in order to find the second equation that contains the point (4,5).

y - 5 = 5(x-4)
y = 5x - 20 + 5
y = 5x -15

Therefore, the correct answer is the first option.

Y = 5x + 1...the slope here is 5...a parallel line will have the same slope.

y = mx + b
slope(m) = 5
(4,5)...x = 4 and y = 5
now we sub and solve for b, the y int
5 = 5(4) + b
5 = 20 + b
5 - 20 = b
-15 = b
so ur parallel equation is : y = 5x - 15