Insert two arithmetic means between 21 and 33

25 and 29

Step-by-step explanation:

let the two arithmetic mean be b and c respectively.

U(1)=21 and since it is the first term then, a=21

2nd term that is U(2)=b

3rd term that is U(3)=c

4th term that is U(4)=33

Now U(2)=(a+d) that is b

U(3)=(a+2d) that is c

U(4)=(a+3d) that is the 4th term

find d using the 4th term

a+3d=33

21+3d=33

3d=33-21

3d=12

d=12÷33

d=4

therefore

b= a+d ( second term)

b=21+4

b=25

then

c=a+2d ( 3rd term )

c=21+2×4

c=21+8

c=29

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1