The larger of two consecutive ODD numbers is one less than twice the smaller number. Find the larger of the two numbers.

Step-by-step explanation:

z -  any integer

2z+1 - any odd integer (the smaller one)

2z+1+2 = 2z+3 - odd integer consecutive to 2z+1  (the larger one)

2(2z+1)    - twice the smaller number

2(2z+1) - 1    - one less than twice the smaller number

2(2z+1) - 1 = 2z + 3

4z + 2 - 1 = 2z + 3

2z = 2

 z = 1

2z+3 = 2•1+3 = 5

check:

2z+1 = 2•1+1 = 3,  

2(2z+1)-1 = 2(2•1+1)-1 = 2•3-1 = 5 = 2z+3

do have an equation or graph or

step-by-step explanation: