What is the midpoint of the line segment? Drag the coordinates to the boxes to correctly match the endpoints and midpoint.

The midpoint of a line segment divides the line segment into 2.

The midpoint is calculated as follows:

Hence, the midpoint of is

The midpoint is calculated as follows:

Hence, the midpoint of is

Read more about midpoints at:

link

Hey there! I'm happy to help!

LINE SEGMENT 1

To find the x value of the midpoint, you add the x values and divide by 2.

-1/3+4/3=1

1/2=1/2

For the y value, you add the y values and divide by 2.

7/5+5/2= 3 9/10

3 9/10÷2=1 19/20 or 39/20.

So, our midpoint is (1/2, 39/20).

LINE SEGMENT 2

X-Values

5+(-1)=5-1=4

4/2=2

Y-Values

√3+5√3=6√3

6√3÷2=3√3

So, our midpoint is (2, 3√3).

Have a wonderful day! :D

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!