5. Box A contains one white ball and two red balls. Box B contains one white ball and three red balls. A ball is picked at random from box A and put into box B and mixed around. A ball is then picked at random from box B. What is the probability that this final pick is white

7/12

Step-by-step explanation:

given data:

Box A

white ball = 1

red ball = 2

total ball = 3.

Box B

white ball = 1

red ball = 3

total ball = 4

Probability of picking a white ball as the final pick.

= 1/3 + 1/4

get the LCM = 12

= 4*1 + 1*3 /12

= 4 + 3 /12

= 7/12

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

i think the correct option is the second option.