the length of a rectangle is 3 inches more than it’s width. if the perimeter is 42 inches, find the dimensions of the rectangle

length = 12

width = 9

Step-by-step explanation:

We can use a system of linear equations to solve this problem. Lets make the variable L represent length and W represent width.

So we know that the length is 3 more than the width. An equation for this would be:

W = L - 3

We also know that the perimeter is 42 inches. The perimeter of a rectangle, using the variables L and W, is 2L + 2W, or 2(L + W). Using this, we can make the equation:

2(L + W) = 42

We can simplify the last equation by dividing both sides by 2:

L + W = 21

So now we have the two equations:

W = L - 3

L + W = 21

From here, there are multiple ways this question can be solved. I am going to use the substitution method here.

Knowing that W = L - 3, we can replace W in the second equation with L - 3.

L + L - 3 = 21

Add 3 to both sides.

2L = 24

Divide both sides by 2.

L = 12

Now we know that L = 12. Using this, we can replace L with 12 in the first equation to solve for W.

W = 12 - 3

W = 9

So:

L = length = 12

W = width = 9

I hope you find my answer helpful.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

the answer is 3/2 and for decimal: 1.5

hope i

-lavira: )