Mathematics, 09.09.2020 14:01, king845

the identity (x^2+y^2)^2 = (x^2+y^2)^2 + (2xy)^2 can be used to generate pythagorean triples. what pythagorean triple could be generated using x=8 and y=3

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the identity (x^2+y^2)^2 = (x^2+y^2)^2 + (2xy)^2 can be used to generate pythagorean triples. what p...