Find k so that the distance from (–1, 1) to (2, k) is 5 units.

k = -3 or 5

Step-by-step explanation:

The given parameters are;

The line extends from points (-1, 1) to point (2, k)

The length of the line = 5 units

The formula for the length, l, of a line given its coordinates can be  found by the following formula;

Therefore, we have;

Which, by squaring both sides, gives;

25 = (k - 1)² + (2 - (-1))² = (k - 1)² + (2 + 1)² = (k - 1)² + 3²

25 = (k - 1)² + 3² = k² - 2·k + 1 + 9

25 - 25 = 0 = k² - 2·k + 1 + 9 - 25 = k² - 2·k - 15

0 = k² - 2·k - 15

0 = (k +3) × (k - 5)

Therefore, k = -3 or 5

When k - -3, we have;

When k = 5, we have;

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.