15 I am buying stationery for use in the office. I have 23 staff in the office and need to get 2 pens and 1 notebook for each of them. The pens are sold in packets of either 10 or 12 and the
notebooks are sold in packets of 8 or 10. I decided to buy just the larger packets of each and
save any extra ones. I told my assistant how many packets of pens, and notebooks to buy, but
when he returned I found that he had bought the smaller packets in each case. I am going to buy
sufficient extra pens and notebooks that I need for my staff singly. A single pen will cost 12¢ and
a single notebook will cost 35¢.
How much do I need to pay for the extra pens and notebooks?

according to egenuity the answer is

step-by-step explanation:

d. 344.22

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

abby has a greater debt becasue she owea 5 more then alan does