Find the equation of a line that contains the points (−2,3) and (0,8). Write the equation in slope-intercept form, using fractions when required.

Hey there! I'm happy to help!

First we need to find the slope, which is the incline of the line. To do this, you divide the difference of the y values by the difference of the the x values.

3-8=-5

-2-0=-2

-5/-2=5/2

To find the y-intercept, you want to find where the line hits the y-axis. Well, the point (0,8) tells us that the y-intercept is 8. The y-axis is where x=0, so our y-intercept is 8.

Slope intercept form is y=mx+b, where m is the slope and b is the y-intercept.

So

y=5/2x+8.

Have a wonderful day! :D

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

21

step-by-step explanation: