Consider the function and its inverse. f(x) = x2 + 4 and f-1(x) = - - 4 When comparing the functions using the equations, which conclusion can be made? The domain of f(x) is restricted to x 20, and the domain off'(x) is restricted to x20. The domain of f(x) is restricted to x 0, and the domain off'(x) is restricted to xs 0. The domain of f(x) is restricted to x < 0, and the domain off'(x) is restricted to x2 4. The domain of f(x) is restricted to xs o, and the domain of f'(x) is restricted to xs 4.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer is : muchas/tipicas

have a nice day!

~recklesschicken

my answer is$ 12

step-by-step explanation:

because 15 -2=12