(AM GIVING BRAINLIEST) Find all values of x such that x/(x - 5) =4/(x - 4)

x = imaginary number

x₁ = 2i

x₂ = 6i

Step-by-step explanation:

x/(x - 5) =4/(x - 4)

x(x-4) = 4(x-5)

x*x + x*-4 = 4*x * 4*-5

x² -4x = 4x - 20

x² -4x - 4x + 20 = 0

x² - 8x + 20 = 0

x = {-(-8)±√((-8²)-(4*1*20))} / (2*1)

x = {8±√(64-80)} / 2

x = {8±√-16} / 2

√(-16) ∈ i

i =  set of imaginary numbers

√-16 = -4i

then:

x = {8±(-4i) } / 2

x₁ = {8+(-4i)}/2 = {8-4i)/2 = 4i/2 = 2i

x₂ = {8-(-4)}/2 = {8+4i}/2 = 12i/2 = 6i

Step-by-step explanation:

i wish i could u

step-by-step explanation:

i wish i could u

my guess would be b and d, but i didn’t actually get out the pen and paper. lol