A soccer player is going to kick a soccer ball from one corner of a field to the opposite corner. If the field is 72 meters long and 54 meters wide, how far will the soccer player have to kick the ball?

Below

Step-by-step explanation:

The corners are the vertices of the rectangle

So to Kick the ball from the corner to the opposite one the player must kick far enough to cross all the width.

The width is 54 m

Then the distance needed is 54 m at least if the ball goes straight.

He will kick is 90 m

Step-by-step explanation:

We can use the Pythagorean theorem to solve

a^2 + b^2 = c^2

72^2 + 54^2 = c^2

5184+2916=c^2

8100 = c^2

Take the square root of each side

sqrt(8100) = sqrt(c^2)

90 = c

He will kick is 90 m

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40