If d (x) = 2 x + 1, find d(-3) =

d(-3) = -5

Step-by-step explanation:

To find d(-3), plug in -3 wherever there is an x in d(x).

d(x) = 2x + 1

d(-3) = 2(-3) + 1

d(-3) = -6 + 1

d(-3) = -5

d(-3) = -5

Step-by-step explanation:

To find the answer substitute x for -3

This means the equation will now look like

d(-3) = 2(-3) + 1

d(-3) = -6 + 1

d(-3) = -5

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629