the length of a rectangle is 4 feet more than its width. The area of the rectangle is 60ft^2. Find the length and width of the rectangle.

10 and 6

Step-by-step explanation:

Let A be the area of the rectangle, w the width and L the length

● A = w*L

The length is 4 feet more that the width so L = w+4

● A = w ×(w+4)

● A = w^2 + 4w

The area is 60 ft^2

● w^2 + 4w = 60

Substract 60 from both sides

● w^2 + 4w - 60 = 0

This a quadratic equation

We will solve it by graphing it

The solution are 6 and -10 since the graph intersect with the x-axis in those points (pictures below)

The width is 6 feet long since it is a distance and a distance is always positive.

● w = 6

● L = w + 4

● L = 6 + 4

● L = 10

The width is 6 feet and the length is 10 feet

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17