A stadium charges $85 for each seat in section A, $55 for each seat in section B, and $30 for section C. There are three times
as many seats in section B as in section A. The revenue from
selling all 19,600 seats is $770,000.
a) Write a system to represent the situation.
b) Solve the system from part (a), write your solution in (x, y, z)
form.

(x,y,z)=(1400, 4200,14000)

Step-by-step explanation:

x*85+3*x*55+y*30=770.000

x+3x+y=19600

250x+30y=770.000

4x+        y=19600         /*-30

250x +30y= 770 000

-120x -30y= - 588.000

250x-120x  = 182 000

130 x= 182000

x=182000/130

section A   x=1400 seats

section B    3x=3*1400=4200 seats

section C   y=19600-4*1400=19600-5600=14000 seats

it would be 3 ÷by 6 because the number on each side