![f(x) = 4 + x^2 + tan [\frac{ \pi x}{2} ]](/tpl/images/0743/3626/dcff7.png)
, -1 < x < 1 a = 4 
![4 + x^2 + tan[\frac{\pi x }{2} ] = 4](/tpl/images/0743/3626/d1f1d.png)
![x^2 + tan[\frac{\pi x }{2} ] = 0](/tpl/images/0743/3626/65e26.png)
![f(0) = 4+0^2 + tan [\frac{ \pi * 0}{2} ]](/tpl/images/0743/3626/73a74.png)
Find (f −1)'(a).
f(x) = 4 + x2 + tan(πx/2), −1 < x < 1, a = 4...
Mathematics, 05.09.2020 19:01, clevens123
Find (f −1)'(a).
f(x) = 4 + x2 + tan(πx/2), −1 < x < 1, a = 4
Answers: 2
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