Point N is on line segment \overline{MO} MO . Given MN=x, MN=x, MO=3x-6,MO=3x−6, and NO=x+1,NO=x+1, determine the numerical length of \overline{MO}. MO

Step-by-step explanation:

if point N is located on the line segment MO, then MN + NO = MO. Given the following value of each line segment MN=x, MO=3x-6, and NO=x+1, to get MO, we need to first get the value of x by substituting the given functions into the expression above as shown to have;

x + x+1 = 3x - 6

2x + 1 = 3x -6

collect like terms

2x - 3x = -6-1

-x = -7

x = 7

Then we can get the numerical length of MO by substituting x = 7 into the function MO = 3x - 6

MO  = 3(7)-6

MO = 21-6

MO =15

Hence, the numerical length of MO is 15units.

last option: rhombus or kite

step-by-step explanation:

a kite and rhombus have the same shape. as we don't have any specific formula for the calculation of area of kite. the diagonals are used to calculate the area of a kite or rhombus.

the formula for area of rhombus is given by:

here, d_1 is the first diagonal and d_2 is the second diagonal.

so,

last option is the correct answer ..

need more info

step-by-step explanation: