Help please? 10 points

  277 cm^2

Step-by-step explanation:

Two of the triangular faces will have areas of ...

  A = 1/2bh = (1/2)(8 cm)(11 cm) = 44 cm^2

and the other two will have areas of ...

  A = 1/2bh = (1/2)(9 cm)(13 cm) = 58.5 cm^2

The base will have an area of ...

  A = LW = (9 cm)(8 cm) = 72 cm^2

So, the total area will be ...

  2(44 cm^2) +2(58.5 cm^2) +72 cm^2 = 277 cm^2

Comment on the problem

You could not actually build this pyramid. The height of the peak above the 8-cm edges must be ...

  √(11^2 -(4.5)^2) = 10.04 cm

The height of the peak above the 9-cm edges must be ...

  √(13^2 -4^2) = 12.37 cm.

The peak cannot be in two places at once. This geometry is impossible.

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk