Given the following functions, find each of the values: f(x) = x2 + x - 30
g(x) =x- 5
(f + g)(-5)
(f - g)(3) =
(f. g)(-3) =
(f/g) (1) =

Step-by-step explanation:

(F+g) (-5)

={2x+x-30 +(x-5)}(-5)

={4x-35}(-5)

= -20x +175

X=175/20

X=35/4

X=8.75

(f - g)(3)

={x2 + x - 30 - (x- 5)} (3)

= {2x - 25} (3)

=6x-75

X=75/6

X=12.5

(f.g)(-3)

= {(x2 + x - 30). (x- 5)} (-3)

={(3x-30)(x-5)}(-3)

the answer is a) y= 2 csc [0.5 (x+pi/2)]-1

step-by-step explanation:

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0