3x-5)(x2+2x+1) Please show working

3x^3 + x^2 -7x -5

Step-by-step explanation:

(3x-5)(x^2+2x+1) you multiply and then add to get to 3x^3 + x^2 -7x -5.

*For example (x+2)(x+3) will be x^2+5x+6 The same logic is applied.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐